(8x^2)-(57x)+(54)=0

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Solution for (8x^2)-(57x)+(54)=0 equation: 



(8x^2)-(57x)+(54)=0

a = 8; b = -57; c = +54;
Δ = b2-4ac
Δ = -572-4·8·54
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-39}{2*8}=\frac{18}{16}
=1+1/8
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+39}{2*8}=\frac{96}{16}
=6
$

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